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0=-1.9x^2+18x-19
We move all terms to the left:
0-(-1.9x^2+18x-19)=0
We add all the numbers together, and all the variables
-(-1.9x^2+18x-19)=0
We get rid of parentheses
1.9x^2-18x+19=0
a = 1.9; b = -18; c = +19;
Δ = b2-4ac
Δ = -182-4·1.9·19
Δ = 179.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-\sqrt{179.6}}{2*1.9}=\frac{18-\sqrt{179.6}}{3.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+\sqrt{179.6}}{2*1.9}=\frac{18+\sqrt{179.6}}{3.8} $
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